Twelve problems with three addends each, and every one of them hides a pair that makes ten. The instruction says so outright: look for two numbers that make 10, then add the last number. Some pairs sit side by side, as in 2 + 8 + 3, and others are split apart, as in 7 + 3 + 6 or 8 + 6 + 4, which is the harder and more useful case. Every sum lands between 11 and 18.
The point here is not really three-number addition, it is that addends can be rearranged. A child who finds the ten first turns a three-step problem into a one-step problem, and that habit pays off for years. Expect the split pairs to need a prompt the first time through.